+0  
 
0
95
1
avatar+771 

The length of a tree is 130 feet when the angle of elevation to the sun is \(\theta\).

     a) Write the height of the tree as a function of \(\theta\).

     b) If \(\theta=25^o\), find the height of the tree.

     c) Rewrite your function in part a so that \(\theta\) is a function of the height of the tree.

     d) If the height of the tree is 100 feet, what is the angle of elevation?

AdamTaurus  Feb 21, 2018

Best Answer 

 #1
avatar+12266 
+1

A. Height of tree = 130 ft  x tan theta

B.  130 * tan (25) = 60.62 ft

C  Tan theta = (tree height) / (shadow length)

D   tan theta =   100/130

         theta = arctan (100/130) = 37.57 dgrees

ElectricPavlov  Feb 21, 2018
Sort: 

1+0 Answers

 #1
avatar+12266 
+1
Best Answer

A. Height of tree = 130 ft  x tan theta

B.  130 * tan (25) = 60.62 ft

C  Tan theta = (tree height) / (shadow length)

D   tan theta =   100/130

         theta = arctan (100/130) = 37.57 dgrees

ElectricPavlov  Feb 21, 2018

10 Online Users

avatar
New Privacy Policy (May 2018)
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  Privacy Policy