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The length of a tree is 130 feet when the angle of elevation to the sun is \(\theta\).

     a) Write the height of the tree as a function of \(\theta\).

     b) If \(\theta=25^o\), find the height of the tree.

     c) Rewrite your function in part a so that \(\theta\) is a function of the height of the tree.

     d) If the height of the tree is 100 feet, what is the angle of elevation?

 Feb 21, 2018

Best Answer 

 #1
avatar+37146 
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A. Height of tree = 130 ft  x tan theta

B.  130 * tan (25) = 60.62 ft

C  Tan theta = (tree height) / (shadow length)

D   tan theta =   100/130

         theta = arctan (100/130) = 37.57 dgrees

 Feb 21, 2018
 #1
avatar+37146 
0
Best Answer

A. Height of tree = 130 ft  x tan theta

B.  130 * tan (25) = 60.62 ft

C  Tan theta = (tree height) / (shadow length)

D   tan theta =   100/130

         theta = arctan (100/130) = 37.57 dgrees

ElectricPavlov Feb 21, 2018

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