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# Trig Graphing

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Consider the following points on the graphs of $$y = \cos{x}$$ and $$y = \cos{\frac{x}{2}}$$ with the added vertical dashed lines: Find C and D

I tried finding the cosine of points a and b but not sure how I continue here

Jan 30, 2023
edited by YourAverageDummy  Jan 30, 2023

#5
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B= 4/8 C=4/8

Jan 31, 2023
#6
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Sorry C is -1/8

Ds1234  Jan 31, 2023
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no but I would be interested how you came to that solution

YourAverageDummy  Jan 31, 2023
#8
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I think there are a couple of different ways to take lthis question.

Looking at the graph I can see that  b=a+2pi

From a to b is a whole wavelength of  cos a   and a half a wavelength of cos (a/2)

This means that

1-d = c - - 1

1-d= c+1

c=-d

$$cos\;a= \frac{1}{8}\\ cos(\frac{a}{2}+\frac{a}{2})=\frac{1}{8}\\ cos^2(\frac{a}{2})-sin^2(\frac{a}{2})=\frac{1}{8}\\ cos^2(\frac{a}{2})-(1-cos^2(\frac{a}{2}))=\frac{1}{8}\\ 2cos^2(\frac{a}{2})-1=\frac{1}{8}\\ 2cos^2(\frac{a}{2})=\frac{9}{8}\\ cos^2(\frac{a}{2})=\frac{9}{16}\\ cos(\frac{a}{2})=\pm\frac{3}{4}\\ \text{discount the positive answer}\\ c=cos(\frac{a}{2})=-\frac{3}{4}\\$$

$$d=\frac{3}{4}$$

Jan 31, 2023
edited by Melody  Jan 31, 2023
#9
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huh. I never thought that you could prove c in terms of d
Thanks Melody!

Jan 31, 2023
#10
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You are welcome :)

Melody  Feb 1, 2023