compute the smallest positive real solution to the equation sin(7x) = cos (3x − π/14) + 2.

Hints/starting ideas would be appreciated.

Guest Jun 19, 2021

#1**+1 **

Well, will it help to know that the desired smallest positive x is in the interval (1.1, 1.2)?

Bginner Jun 20, 2021

#2**+1 **

sin(7x) = cos (3x − π/14) + 2

cos(7x - pi/2) = cos(3x − π/14) + 2

Note that cos(a) has to return a number from -1, to 1.

So the only way this equation is possible is if cos(3x − π/14) = -1 and cos(7x - pi/2) = 1.

cos(3x − π/14) = -1

cos(7x - pi/2) = 1

Can you take it from here?

=^._.^=

catmg Jun 20, 2021