compute the smallest positive real solution to the equation sin(7x) = cos (3x − π/14) + 2.
Hints/starting ideas would be appreciated.
+287 Well, will it help to know that the desired smallest positive x is in the interval (1.1, 1.2)?
+2407 sin(7x) = cos (3x − π/14) + 2
cos(7x - pi/2) = cos(3x − π/14) + 2
Note that cos(a) has to return a number from -1, to 1.
So the only way this equation is possible is if cos(3x − π/14) = -1 and cos(7x - pi/2) = 1.
cos(3x − π/14) = -1
cos(7x - pi/2) = 1
Can you take it from here?
=^._.^=
