We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
92
9
avatar+13 

Can someone please help me understand how to break this down, this was no where in my homework or lecture but on the test twice?

 

Linking screenshots of the quetsions

 

 

 Sep 19, 2019
 #1
avatar
+1

Hello,

The first question: 

So, the first question wants us to find a side "x" with a given angle & a side length 

and It also gives us that:

x=7cot(39)

so 39 is the angle in (degrees) 

well you might be questioning what is 7?? 

Let's first know cot

cot is co-tangent

We also know that cotangent= Adj/opposite

While tangent=Opposite/Adj

Let's first find cot(39) 

cot(39)= Adj/opp = x/7

Well we want to solve for x

Since we know that Cot(39)=x/7

Therefore let's multiply both sides by 7 

we conclude that:

7*Cot(39)=x 

So let's look at triangles..

The correct triangle have the following just from the information we got: 

1-the opposite side of the angle is =7

2-The adjacent is x

F. is the correct :) 

you chose "E." You simply found tangent. 

because tangent = opp/adj while cotangent=adj/opp 

 

 

Second question: 

Again we have:

4 cos 29 

where 29 is the angle in (degrees) 

and 4 is a side (We will know soon) 

Well first let's know cosine

cos 29=adj/hyp

so let's find the adj side to cos 29 

Well it must be "x" because cos(29)=x/4

so multiplying both sides by 4 we get that 4*cos(29)=x 

So option E. Is correct. Also notice that X and 4 can't be the opposite side of the angle because cosine is adj/hyp 

 

Hope that helped :) and good luck! 

 Sep 19, 2019
 #2
avatar+13 
+1

You're a life saver thank you!

SoulAbility  Sep 19, 2019
 #3
avatar+13 
+1

I tried applying that to another question, and I for the life of me can't understand why the hypotenuse is x on this one.

 

I'll show you my notes and the question, hopefully you're still around to explain what I did wrong. 

 

Sorry.

 

 

 

SoulAbility  Sep 19, 2019
 #4
avatar+19838 
+2

sec = 1/cos = 1/(adj/hyp) = hyp/adj

 

From your Q    x=3 hyp/adj  of the angle    x = 3 x/3      of the 42 angle

 Sep 19, 2019
 #5
avatar+13 
+1

I see where i messed up thx

SoulAbility  Sep 19, 2019
 #6
avatar
0

Don't hesitate to ask questions. :)

Guest Sep 19, 2019
 #7
avatar
0

 

Just a pattern I noticed: 

x=3 sec 42

let it be in that form: 

x= r sec z (angle)

sec z= r/f 

where f is the adjacent side. (Changes depends on the trigonometric  function etc) 

while r is the hypotenus 

so r=hyp. 

in this case: 

x= 3 sec 42

r=3 

so x is the adjacent according to the trigonometric function sec hyp/adj

Guest Sep 19, 2019
 #8
avatar+13 
+1

Thx, I got it now, aced my test also :D

 

Pattern I went with made it so easy for me,

 

I can just take x=7cot(39)

 

divide the 7 out right away so that x over something = cot(theta)

 

x/7 = cot39

 

Then just set trig function what side it represents, in this case adj/op

 

x/7 = a/o

 

and it matches up every time x=a and 7=o adjusted to theta 

SoulAbility  Sep 19, 2019
 #9
avatar
0

Well done!!! :) 

Guest Sep 20, 2019

16 Online Users

avatar
avatar