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The line with equation -a+3b=0 conincides with the terminal side of an angle 0 (with a line through it) in standard position and sin 0 (line through it) < 0

 

What would the value of cos 0 (with a line through it)?

 Jan 20, 2020
 #1
avatar+110206 
0

Does this comewith a picture?

lines usually use x and y.

 Jan 20, 2020
 #2
avatar+24 
+1

Nope, this is all there is.

JohnLester1  Jan 20, 2020
 #3
avatar+110206 
0

So the question is:

 

The line with equation -a+3b=0       (is this one meant to be zero ?) 

 

conincides with the terminal side of an angle Ø

in standard position and sin Ø   < 0

 

What would the value of cos Ø  ?  If sin is negative then cos is positive.  (4th quadrant)

 

It still makes no sense to me.

 Jan 20, 2020
 #6
avatar+24 
+1

Yes, that is the question. Also where did you find that special 0 with a line throguh it I was refereing to. I checked special characters and I could not find it. In any case yes that is the question.

JohnLester1  Jan 20, 2020
 #7
avatar+110206 
+2

 

This is whater to find it

 

Melody  Jan 20, 2020
 #4
avatar+12327 
+1

Maybe it's meant to be.

laugh

 Jan 20, 2020
 #5
avatar+110206 
+1

Danke Omi,

Vielleicht, aber ich denke, es muss im vierten Quadranten sein.

Melody  Jan 20, 2020

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