The line with equation -a+3b=0 conincides with the terminal side of an angle 0 (with a line through it) in standard position and sin 0 (line through it) < 0
What would the value of cos 0 (with a line through it)?
So the question is:
The line with equation -a+3b=0 (is this one meant to be zero ?)
conincides with the terminal side of an angle Ø
in standard position and sin Ø < 0
What would the value of cos Ø ? If sin is negative then cos is positive. (4th quadrant)
It still makes no sense to me.
Yes, that is the question. Also where did you find that special 0 with a line throguh it I was refereing to. I checked special characters and I could not find it. In any case yes that is the question.