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In right triangle JKB, angles J and B are complementary angles.  If cos J = 9/12, what is the value of sin B?

 

 Feb 25, 2021
 #1
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Since sine and cosine are opposite trig functions, sin(B) is also 9/12 or 3/4

 Feb 25, 2021
 #2
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\(\angle J\) and \(\angle B\) are complementary => \(\angle J + \angle B = 90^\circ\) => \(\angle B = 90^\circ - \angle J\)

 

\(\sin B = \sin(90^\circ - J) = \cos J = \dfrac 9 {12} =\dfrac34\)

 Feb 25, 2021
 #3
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Asker can you please tell me what complimentary means?   Do you know?

If you don'r know then look it up.

Either way please answer my question.

 Feb 25, 2021

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