In right triangle JKB, angles J and B are complementary angles. If cos J = 9/12, what is the value of sin B?
Since sine and cosine are opposite trig functions, sin(B) is also 9/12 or 3/4
∠J and ∠B are complementary => ∠J+∠B=90∘ => ∠B=90∘−∠J
sinB=sin(90∘−J)=cosJ=912=34
Asker can you please tell me what complimentary means? Do you know?
If you don'r know then look it up.
Either way please answer my question.