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If you let (7,-2) be a point on the terminal side of theta, what are the exact values of:

 

cos(theta):

sec(theta):

cot(theta):

 Mar 8, 2019
 #1
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This angle is in the 4th quadrant......the cos and sec will be positive...the cot will be negative

 

We need to find "r" .....  this   is given by :     sqrt ( 7^2  + (-2)^2 )   sqrt (49 + 4) =  sqrt(53)

 

cos  = x /r  =   7/sqrt (53)  =  7sqrt (53) /53

sec = reciprocal of cos  =   sqrt (53) /7

cot  = x / y  =  7/-2    = -7/ 2

 

 

 

cool cool  cool

 Mar 8, 2019

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