Trig

That really didn't help much.. but thanks for trying!(:

Kitsune123:

1. If COS A=(3/5), Find TAN A (As a fraction)

2. If Sec(x)=(25/7), find SIN(x) (As a fraction)

3. Change 7pi/4 to degrees

4. Find SIN pi/2

For number 1 - Each trig function denotes the ratio of the different sides of a triangle. If you recall, SIN represents the ratio of Opposite/Hypotenuse (The handy acronym SohCahToa, is always useful in remembering). In this equation you want to find TAN, and that is Opposite/Adjacent. Well, we know from the SIN ratio that the 'opposite' side is 3. So far, 3/Adjacent. Well, we can use Pythagorean's Theorem to find the 'adjacent' side (we'll call it 'a'):
3^2 + a^2 = 5^2
9 + a^2 = 25
a^2 = 16
adjacent = 'Plus or Minus' 4
TAN is therefore "plus or minus" 3/4.

For number 2 - The same method is used, so I'll skip a wordy explanation:
Sec(x) = 1/Cos(x), and therefore, is Hypotenuse/Adjacent (You can use the acronym ChoShaCao for the reciprocal identities). Since SIN is Opposite/Hypotenuse, we have Opposite/25. Use Pythagorean's Theorem to find the third side:
7^2 + o^2 = 25^2
49 + o^2 = 625
o^2 = 576
opposite = "plus or minus" 24
SIN is therefore "plus or minus" 24/25.

For number 3 - a simple conversion from PI to degrees is to multiply your problem by 180 degrees/PI. Here you multiply 7 PI/4 by 180 degrees/PI, which in this case is 315 degrees.

For number 4 - You can use a calculator for this one: 1.57
OR
If you have gone over the Unit Circle already, remember that SIN represents the 'y' axis. You can write SIN of PI/2 as Sqrt(2) / 2.

Hope this helps
~Nicholas

Thanks!(: That actually helped a lot!(: but do you mind helping me with the second half of the problem? It's a two part problem and that is only the first half. This is the second half! Thanks SOOOO much if you can help!!!<3(:
[size=150]Round the following to the nearest integer: 10 times the product of answers 3 and 4, all raised to the power of the product of answers 1 and 2.[/size]

-Lizzy(:

Kitsune123:

Thanks!(: That actually helped a lot!(: but do you mind helping me with the second half of the problem? It's a two part problem and that is only the first half. This is the second half! Thanks SOOOO much if you can help!!!<3(:
[size=150]Round the following to the nearest integer: 10 times the product of answers 3 and 4, all raised to the power of the product of answers 1 and 2.[/size]

-Lizzy(:

you are lazy!! smh