An airplane flies from A to B 500 km away in the direction 90° and then to C 700 km north of A. How long is the flight from B to C? What is the flight’s bearing?

Guest May 14, 2020

#1**+1 **

We will have a right triangle with AB , AC being the legs and BC the hypotenuse

To find BC we have

BC = sqrt [ 500^2 + 700^2] ≈ 860.23 mi

To find the bearing we have

tan BCA = (500/700) = 5/7

arctan (5,7) = BCA ≈ 35.53°

I'm not sure how you want to denote the bearing, but one way is

N 35.53° W

CPhill May 14, 2020