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An airplane flies from A to B 500 km away in the direction 90° and then to C 700 km north of A. How long is the flight from B to C? What is the flight’s bearing?

 May 14, 2020
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We will have a right triangle  with AB , AC being the legs  and BC  the  hypotenuse

 

To find  BC  we have

 

BC = sqrt [ 500^2  + 700^2]  ≈ 860.23 mi

 

To find  the  bearing  we  have

 

tan  BCA   = (500/700)  = 5/7

 

arctan (5,7)  =  BCA  ≈ 35.53°

 

I'm not sure  how  you want to denote the bearing, but  one  way is

 

N 35.53° W

 

 

cool cool cool

 May 14, 2020
edited by CPhill  May 14, 2020

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