\(\frac{10}{sin(c)}=\frac{8}{sin(65)}\) Forgot how to figure this out.
Cross-multiply: 10 x sin(65) = 8 x sin(c)
Change sides: 8 x sin(c) = 10 x sin(65)
Divide by 8: sin(c) = 10 x sin(65) / 8
Find the inverse sin: c = sin-1( 10 x sin(65) / 8 )
But since 10 x sin(65) / 8 > 1, there is no answer!
Oh thanks.
+333 
