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QUESTTION 1:

A sine function has the following key features:

Frequency = 1/8π

Amplitude = 6

Midline: y = 3

y-intercept: (0, 3)

The function is not a reflection of its parent function over the x-axis.

Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

 

Here is my problem, im not sure on how graphing works on this mecanism, and i was wondering if you can help me on where to put the sines on the x and y axises 

 Feb 5, 2019

Best Answer 

 #1
avatar+17331 
+2

It is a sin function    so   start with   sin x

It is NOT a reflection so it is NOT -sin x        still sin x

 

Frequency = 1/(8pi)    period = 1/f =   8pi          2pi / (8pi) = 1/4     now we have    sin (1/4  x)

 

Amplitude = 6       Now we have     6 sin (1/4  x)

Midline 3                                          6 sin (1/4 x) + 3

 Feb 5, 2019
 #1
avatar+17331 
+2
Best Answer

It is a sin function    so   start with   sin x

It is NOT a reflection so it is NOT -sin x        still sin x

 

Frequency = 1/(8pi)    period = 1/f =   8pi          2pi / (8pi) = 1/4     now we have    sin (1/4  x)

 

Amplitude = 6       Now we have     6 sin (1/4  x)

Midline 3                                          6 sin (1/4 x) + 3

ElectricPavlov Feb 5, 2019

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