+0  
 
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avatar+1828 

which one is correct and why  

 

 

 

 

 

xvxvxv  Feb 10, 2015

Best Answer 

 #1
avatar+80875 
+10

d/dx ( sin^4/4 - sin^6/6 + C) =

sin^3x(cosx) - sin^5x(cosx) =

cosx(sin^3x)(1 - sin^2x) =

cosx (sin^3x)(cos^2x) =

sin^3xcos^3x

And           

d/dx(-cos^4x/4 + cos^6x/6 + C)=

-(sinx)(-cos^3x)   - (sinx)cos^5x  =

(sinx)(cos^3x)(1 - cos^2x) =

(sinx)(cos^3x)(sin^2x) =

(cos^3x)(sin^3x)  = sin^3xcos^3x

And they are exactly the same.....!!!

 

CPhill  Feb 10, 2015
Sort: 

2+0 Answers

 #1
avatar+80875 
+10
Best Answer

d/dx ( sin^4/4 - sin^6/6 + C) =

sin^3x(cosx) - sin^5x(cosx) =

cosx(sin^3x)(1 - sin^2x) =

cosx (sin^3x)(cos^2x) =

sin^3xcos^3x

And           

d/dx(-cos^4x/4 + cos^6x/6 + C)=

-(sinx)(-cos^3x)   - (sinx)cos^5x  =

(sinx)(cos^3x)(1 - cos^2x) =

(sinx)(cos^3x)(sin^2x) =

(cos^3x)(sin^3x)  = sin^3xcos^3x

And they are exactly the same.....!!!

 

CPhill  Feb 10, 2015
 #2
avatar+1828 
0

Thank you CPhill 

xvxvxv  Feb 13, 2015

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