We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.

Hello! I am in an online trigonometry class and we currently have an assignment that asks us to solve this problem. I am slightly confused about it and where to even start. Any assistance on the process to solve this would be so greatly appreciated.


The problem goes as follows:


Two docks are located on an east-west line 2590 feet apart. From dock A, the bearing of a coral reef is 62°24′. From dock B, the bearing of the coral reef is 332°24'. Find the distance from dock A to the coral reef.

The distance from dock A to the coral reef is __ feet. (Round to the nearest integer as needed.)


Thank you for your help in advance. It means alot to me. :)

 Sep 17, 2018

A bearing of 62.24° converts to an angle of 90 - 62.24 = 27.76°


And a bearing of  332.24°  converts to an angle of 332.24 - 270  = 62.24°


So we have a triangle  with angles of  27.76° and  62.24°


And the third angle of the triangle is  180 - 27.76 - 62.24  = 90°


So....we can find the distance from A to the coral reef using the Law of Sines


2590 / sin 90  =  D /  sin 62.24      where D is the distance we want


2590 / = D / sin 62.24       multiply both sides by sin62.24


2590 * sin 62.24  =  D ≈ 2292 ft.


Here's the approximate picture....dock "A" is a (0,0)....the reef is point B...and  dock "B"  is at point C




cool cool cool

 Sep 17, 2018

9 Online Users