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# Trigonometry-Practice Problems

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1. What is the value of x?

sin 64dg=cos x

2. What is the value of x?

sin(x+37)dg=cos(2x+8)dg

3. Given cos x 12/13 and sin x 5/13, what is the ratio for tan x? Answer as a fraction in simplest form.

4.

KenyaRT  Apr 3, 2017
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### 3+0 Answers

#1
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1.

sin 64º = cos xº

sin 64º = sin(90º - xº)

64º = 90º - xº

64º + xº = 90º

x = 90º - 64º

x = 26º

hectictar  Apr 3, 2017
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Thanks

KenyaRT  Apr 3, 2017
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2. What is the value of x?

sin(x+37)dg=cos(2x+8)dg

The sine and cosine are co-functions.....so......the sum of their angles  = 90°  .......so....

x + 37 + 2x +  8   = 90   simplify

3x + 45  = 90       subract 45 from both sides

3x   = 45    divide both sides by 3

x = 15°

3. Given cos x 12/13 and sin x 5/13, what is the ratio for tan x? Answer as a fraction in simplest form.

tan x   = sin x /  cos x     =  (5/13) / (12 / 13)    =    5 / 12

CPhill  Apr 3, 2017

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