A kite is flying at an angle of elevation of about 40 degrees. All 80 meters of string have been let out. Ignoring the sag inn the string, find the height of the kite to the nearest meter. Someone help me figure this out please.
The kite string, the ground, and the height make a right triangle. The kite string is the hypotenuse, 80 meters. The angle between the ground and kite string is 40º.
sin40º = height/80
height = 80sin40º
height ≈ 51.423 meters
We can use the sine to solve this.....
The string length is the hypotenuse and we are looking for the oppsite side.....so we have
sin (40) = h / 80 where h is the height.....multiply both sides by 80
80 * sin (40) = h ≈ 51.42 ft
The kite string is the hypotenuse of a right triangle with the OPPOSITE leg being the height of the kite.
Sin40 = opp/hyp = height/80m
80 x sin 40 = height = 51.m (rounded)