Given cos(k)= negative square root of 3, which is then divided by 2, and 450 degrees < k < 630 degrees, the smallest possible value for k must be ____ degrees.
the smallest possible value for k must be ____ degrees.
Hello Julia!
cos(k)=−√32arccos(−√32)=k∈{(150+n⋅360)deg,(210+n⋅360)deg}
{510deg,570deg} ⊂{k | 450deg < k < 630deg}
The smallest possible value for k must be: k = 510 degrees.
!
cos30∘=−√32 (knowledge from a 30,60, 90 triangle)
2nd or 3rd quad
smallest is 180-30 = 150 next is 180+300=210
next is 150+360= 510 BINGO
Just as asinus said!
+82 
!
