Two planes leave Dawson City Airport at the same time. One airplane travels 420 km/hour. The other airplane travels at 375 km/hour. Two hours later they are 1500km apart. 

Algebraically determine the angle between their paths, rounded to the nearest degree. 

(please solve using trigonometry)

 Jul 27, 2021

Draw a triangle.

Dawsen city aiport is at one vertice  


in 2 hours how far does each plane fly?  Those distances are on the two sides radiating from Dawson city

The other side is 1500km


Use cosine rule to find the angle.

 Jul 27, 2021

In two hours, one airplane has traveled 840 km and the other 750 km.

By the cos rule, we have $1500^2 = 840^2 + 750^2 - 2(750)(840) \cos \gamma$

$981900 = - 2(750)(840) \cos \gamma$

$\cos \gamma = 0.77928571428$

$\gamma = \cos ^{-1} 0.77928571428$

$\gamma = 38.739424597856$

$\gamma = \boxed{39^{\circ}}$

 Jul 27, 2021

Please don't answer over me when I have given a teaching answer.

If a guest needs more help, please let him/her ask for it first.

I do not think that it is usually best for people to be given full answers. 

This should not be just a cheat site.

Melody  Jul 28, 2021

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