+1124 Hi my friends,
Please explain why the turning point for the following equation, is (1;5)
\(y=(2x-1)^2+5\)
Thank you all..
+37146 This is the equation of a bowl shaped parabola with vertex 1/2 , 5 which is the turning point ..... NOT (1,5)
(2x-1)^2 + 5 can be re-written
4(x-1/2)^2 + 5
+118667 Hi Juriemagic,
\(y=(2x-1)^2+5\)
This is the parabola \(y=(2x-1)^2\) that has been lifted up 5 units.
\(y=(2x-1)^2\) is the PARENT equation.
Since the PARENT equation has a double root, that means that the root is the vertex.
The turning point of the PARENT parabola is
2x-1=0
2x=1
x=0.5
So the vertex of the parent equation is (0.5,0)
and the vertex of your equation is 5 units higher, that is (0.5,5)
+1124 oooohhhh I see,
gosh Melody, thank you very much for .."dismanteling" the whole thing for me...you always go the extra mile!!..I can really see your passion in helping others!!!..
