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good morning all the good people!,..(sorry, can't help it, this is my slogan..smiley),

 

If \(f(x)=-2{x^2}+8x+10\), and the turning point is D(2;18), calculate the turning point for f(3x).

 

Question:  I know the equation must change, so does it change to: \(-2{(3)x^2}+8(3){x^2}+10\) ?

which becomes \(-6{x^2}+24{x^2}+10\)

 

I know how to calculate for the turning point, just really want to confirm the change in the equation please...

 

 

(I find myself becoming less and less confident as the days go by.... sad)

 Feb 21, 2019
 #1
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If f(x) = -2x2 + 8x + 10 then f(3x) = -2(3x)2 + 8(3x) + 10 or f(3x) = -18x2 + 24x + 10

 Feb 21, 2019
 #2
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Thank you Alan...appreciated..

juriemagic  Feb 21, 2019

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