+0  
 
0
1213
1
avatar

Two airplanes are spotted on a radar map located at the coordinates (2√2 , - √5 ) and (3√2 , 5√5 ). Determine the distance the airplanes are apart using a calculator to state your answer in decimal form to the nearest hundreds. Assume the coordinates are given so that the distance is in units of miles.

 May 20, 2015

Best Answer 

 #1
avatar+26387 
+8

Two airplanes are spotted on a radar map located at the coordinates (2√2 , - √5 ) and (3√2 , 5√5 ). Determine the distance the airplanes are apart using a calculator to state your answer in decimal form to the nearest hundreds. Assume the coordinates are given so that the distance is in units of miles

$$\binom{x_1}{y_1}=\binom{2\sqrt{2}}{-\sqrt{5}} \qquad
\binom{x_2}{y_2}=\binom{3\sqrt{2}}{5\sqrt{5}}$$

$$\boxed{\rm{distance}~&=& \sqrt { (x_2-x_1)^2 + (y_2-y_1)^2 }}\\\\
\small{\text{$
\begin{array}{rcl}
\rm{distance}~&=& \sqrt { ( 3\sqrt{2} - 2\sqrt{2})^2
+ [ 5\sqrt{5} - (-\sqrt{5}) ]^2 } \\\\
\rm{distance}~&=& \sqrt { ( 3\sqrt{2} - 2\sqrt{2})^2
+ [ 5\sqrt{5} + \sqrt{5} ]^2 } \\\\
\rm{distance}~&=& \sqrt { (\sqrt{2})^2 + ( 6\sqrt{5} )^2 } \\\\
\rm{distance}~&=& \sqrt { 2 + 36\cdot 5 } \\\\
\rm{distance}~&=& \sqrt { 182} \\\\
\rm{distance}~&=& 13.4907375632 \\\\
\rm{distance}~&\approx& 13.49 ~\rm{miles}
\end{array}
$}}$$

 May 20, 2015
 #1
avatar+26387 
+8
Best Answer

Two airplanes are spotted on a radar map located at the coordinates (2√2 , - √5 ) and (3√2 , 5√5 ). Determine the distance the airplanes are apart using a calculator to state your answer in decimal form to the nearest hundreds. Assume the coordinates are given so that the distance is in units of miles

$$\binom{x_1}{y_1}=\binom{2\sqrt{2}}{-\sqrt{5}} \qquad
\binom{x_2}{y_2}=\binom{3\sqrt{2}}{5\sqrt{5}}$$

$$\boxed{\rm{distance}~&=& \sqrt { (x_2-x_1)^2 + (y_2-y_1)^2 }}\\\\
\small{\text{$
\begin{array}{rcl}
\rm{distance}~&=& \sqrt { ( 3\sqrt{2} - 2\sqrt{2})^2
+ [ 5\sqrt{5} - (-\sqrt{5}) ]^2 } \\\\
\rm{distance}~&=& \sqrt { ( 3\sqrt{2} - 2\sqrt{2})^2
+ [ 5\sqrt{5} + \sqrt{5} ]^2 } \\\\
\rm{distance}~&=& \sqrt { (\sqrt{2})^2 + ( 6\sqrt{5} )^2 } \\\\
\rm{distance}~&=& \sqrt { 2 + 36\cdot 5 } \\\\
\rm{distance}~&=& \sqrt { 182} \\\\
\rm{distance}~&=& 13.4907375632 \\\\
\rm{distance}~&\approx& 13.49 ~\rm{miles}
\end{array}
$}}$$

heureka May 20, 2015

3 Online Users

avatar