Two cars travel the same distance. The first car travels at a rate of 41 mph and reaches its destination in t hours. The second car travels at a rate of 54 mph and reaches its destination in 3.7 hours earlier than the first car. How long does it take for the first car to reach its destination? Answer in units of hours.
+129852 Let's call the time it takes the first car to travel the dstance, t.
Then, the time the second car travels is (t - 3.7) hrs. ..... and since the distances are the same, we have
54(t - 3.7) = 41t simplify
54t - 199.8 = 41t rearrange
54t - 41t = 199.8 simplify
13t = 199.8 divde both sides by 13
t = about 15.369 hrs
+427 41mph * thours = Total distance
54mph * 3.7hours = Total distance
Therefore: 41mph * thours = 54mph * 3.7hours
Divide both sides by 41 to make "t" the subject of the equation.
t = (54 * 3.7) / 41
= 199.8 / 41
= 4.8731707317073171
= 4.9hours (to 1 d.p.)
+129852 Let's call the time it takes the first car to travel the dstance, t.
Then, the time the second car travels is (t - 3.7) hrs. ..... and since the distances are the same, we have
54(t - 3.7) = 41t simplify
54t - 199.8 = 41t rearrange
54t - 41t = 199.8 simplify
13t = 199.8 divde both sides by 13
t = about 15.369 hrs
+427 Once again I give incorrect answers because I skim over a detail >_<'
I shall make it my task to read things in their entirety from now on!
