Two numbers are randomly selected without replacement from the set 1-5 Find the probability of each event.

P(Both Even )  =   (2/5) (1/4)  =  2/20  =  1/10

P(Both Prime)  = (3/5)(2/4) =  6/20  =  3/10

P (sum of two numbers is odd)  ....we have C(5,2)  = 10 possible sets

Sets where the sum of two integers is odd :

(1,2) (1,4)

(2,3) (2,5)

(3, 4) 

So...P (Sum of two numbers is odd) =  5/10   =  1/2

P (Product of two numbers is odd)

(1,3) (1,5)

(3, 5)

So.....P (Product of two numbers is odd)  = 3 / 10