Two numbers are randomly selected without replacement from the set 1-5 Find the probability of each event.

Both numbers are even

Both numbers are prime

The sum of the two numbers is odd

The product of the two numbers is odd

Mekka86 Apr 15, 2018

#1**+3 **

P(Both Even ) = (2/5) (1/4) = 2/20 = 1/10

P(Both Prime) = (3/5)(2/4) = 6/20 = 3/10

P (sum of two numbers is odd) ....we have C(5,2) = 10 possible sets

Sets where the sum of two integers is odd :

(1,2) (1,4)

(2,3) (2,5)

(3, 4)

So...P (Sum of two numbers is odd) = 5/10 = 1/2

P (Product of two numbers is odd)

(1,3) (1,5)

(3, 5)

So.....P (Product of two numbers is odd) = 3 / 10

CPhill Apr 15, 2018