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Two numbers are randomly selected without replacement from the set 1-5 Find the probability of each event.

 

Both numbers are even

 

Both numbers are prime

 

The sum of the two numbers is odd

 

The product of the two numbers is odd

 
Mekka86  Apr 15, 2018
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P(Both Even )  =   (2/5) (1/4)  =  2/20  =  1/10

 

P(Both Prime)  = (3/5)(2/4) =  6/20  =  3/10

 

P (sum of two numbers is odd)  ....we have C(5,2)  = 10 possible sets

Sets where the sum of two integers is odd :

(1,2) (1,4)

(2,3) (2,5)

(3, 4) 

 

So...P (Sum of two numbers is odd) =  5/10   =  1/2

 

P (Product of two numbers is odd)

(1,3) (1,5)

(3, 5)

 

So.....P (Product of two numbers is odd)  = 3 / 10

 

 

cool cool cool

 
CPhill  Apr 15, 2018

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