Two numbers that can equal two by adding but equals one in a half by multiply.

By one in a half I take it you mean one and a half.  If so:

 

n + m = 2   so m = 2 - n

 

n*m = 3/2 so n*(2 - n) = 3/2  This can be rearranged as 

 

2n² - 4n + 3 = 0   There are no real number solutions to this.  

 

The complex solutions are \(1\pm i\frac{\sqrt2}{2}\)

 

 

If, on the other hand, by one in a half you meant one half, then the same procedure gives 

 

2n² - 4n + 1 = 0  for which there are real number solutions: \(1\pm \frac{\sqrt2}{2}\)

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Sorry, this website is being very glitchy and not letting me edit what I posted.

 

I meant to type "This is polynomials. I'm thinking the number is prime, but it isn't. Also, it is one in a half like one half (1/2)."