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Let "a" and "b" be two positive integers such that ab + 1 divides a^2 + b^2. Show that: a^2 + b^2 / ab + 1 is the square of an integer.

Guest Mar 18, 2017
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a =2 and b=8, because:

 

2^2+8^2 =68 and 2 x 8 + 1 =17

68/17 =4, which the square of 2.

Guest Mar 18, 2017

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