two years ago a woman was 7 times old as her daughter, but in 3 years time she would be 4 times old as the girl. how old are they now​

d = daughter's age now

w = woman's age now        two years ago    w-2  = 7(d-2)     re-arrange to  w = 7d -12

and

w+3 = 4(d+3)        sub in the red equation

7d-12  +3  = 4d+12

3d = 21

d = 7      then mom = 37                *** edited ***     Thanx  , Guest for noticing my error.....I should have checked my answer !!

EP: You have a typo at this stage:
7d - 12 + 3 =4d +12
7d - 4d =12 + 12 - 3
3d = 21
d = 7 - Daughter's age today
w = 37 - Mother's age today
3 Years from now, Mother will be =40 and Daughter will be = 10