+195 What is the area of a triangle with side lengths $13$, $14$, and $15$?
+201 Herons formula is √s(s−a)(s−b)(s−c), s is the perimiter divided by 2, and a, b, and c are the side lengths. We sum 13, 14, and 15 to get 42, then we plug in the lengths. √42(42−13)(42−14)(42−15)=126√58
+37165 QM....if you ACTUALLY looked at jcx516' s origianl solution....YOU should have been able to spot the minor error made in the calculation .... then you would not have to have been so rude/curt and unappreciative : "that is wrong"
+1223 You can split a 13-14-15 triangle into a 9-12-15 triangle and a 5-12-13 triangle, so the area is 9⋅122+5⋅122=84.
