+0

UHHH

0
53
5
+170

What is the area of a triangle with side lengths $13$, $14$, and $15$?

Feb 28, 2021

#1
+201
+1

Herons formula is $$\sqrt{s(s-a)(s-b)(s-c)}$$$$s$$ is the perimiter divided by 2, and a, b, and c are the side lengths. We sum 13, 14, and 15 to get 42, then we plug in the lengths. $$\sqrt{42(42-13)(42-14)(42-15)}$$$$=\boxed{126\sqrt{58}}$$

Feb 28, 2021
#2
+170
0

that is wrong

QuestionMachine  Feb 28, 2021
#3
+201
+1

The answer is $$\sqrt{7056}=84$$

jxc516  Feb 28, 2021
#5
+30571
0

QM....if you ACTUALLY looked at jcx516' s  origianl solution....YOU should have been able to spot the minor error made in the calculation ....   then you would not have to have been so rude/curt and unappreciative  :     "that is wrong"

ElectricPavlov  Feb 28, 2021
#4
+939
+1

You can split a 13-14-15 triangle into a 9-12-15 triangle and a 5-12-13 triangle, so the area is $$\frac{9 \cdot 12}{2} + \frac{5 \cdot 12}{2} = 84$$.

Feb 28, 2021