We want to split 128 into it's prime factors.
√128=√2⋅2⋅2⋅2⋅2⋅2⋅2
Then we can rewrite this as:
=√2⋅2⋅√2⋅2⋅√2⋅2⋅√2
Now..replace each √2⋅2 with 2
=2⋅2⋅2⋅√2
Multiply the numbers outside the radical together.
=8⋅√2 =8√2
im a sophmore and im curently failing algebra so yea imma be on this sight alot