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sqrt(128)

Best Answer 

 #2
avatar+7155 
+4

We want to split 128 into it's prime factors.

\(\sqrt{128}=\sqrt{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}\)

 

Then we can rewrite this as:

\(=\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt2\)

 

Now..replace each  \(\sqrt{2\cdot2}\)   with 2

\(=2\cdot2\cdot2\cdot\sqrt2\)

 

Multiply the numbers outside the radical together.

\(=8\cdot\sqrt2 \\~\\ =8\sqrt2\)

hectictar  May 4, 2017
 #1
avatar
+2

8rad2

Guest May 4, 2017
 #2
avatar+7155 
+4
Best Answer

We want to split 128 into it's prime factors.

\(\sqrt{128}=\sqrt{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}\)

 

Then we can rewrite this as:

\(=\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt2\)

 

Now..replace each  \(\sqrt{2\cdot2}\)   with 2

\(=2\cdot2\cdot2\cdot\sqrt2\)

 

Multiply the numbers outside the radical together.

\(=8\cdot\sqrt2 \\~\\ =8\sqrt2\)

hectictar  May 4, 2017
 #3
avatar+50 
+2

are you a math major or something you explain it so well

 #4
avatar+7155 
+5

Lol! I am still in high school....though just barely!! laugh

But I really appreciate it! smileysmileysmiley

hectictar  May 4, 2017
edited by hectictar  May 4, 2017
 #5
avatar+50 
+2

im a sophmore and im curently failing algebra so yea imma be on this sight alot

 #6
avatar
+1

I ma in 3rd grade and I can do this problem it's sqrt(2)*8 because 128 is 2^8. it is 8sqrt2

Guest May 6, 2017

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