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# um help pls im not good at math

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sqrt(128)

### Best Answer

#2
+4

We want to split 128 into it's prime factors.

$$\sqrt{128}=\sqrt{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}$$

Then we can rewrite this as:

$$=\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt2$$

Now..replace each  $$\sqrt{2\cdot2}$$   with 2

$$=2\cdot2\cdot2\cdot\sqrt2$$

Multiply the numbers outside the radical together.

$$=8\cdot\sqrt2 \\~\\ =8\sqrt2$$

May 4, 2017

### 6+0 Answers

#2
+4
Best Answer

We want to split 128 into it's prime factors.

$$\sqrt{128}=\sqrt{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}$$

Then we can rewrite this as:

$$=\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt{2\cdot2}\cdot\sqrt2$$

Now..replace each  $$\sqrt{2\cdot2}$$   with 2

$$=2\cdot2\cdot2\cdot\sqrt2$$

Multiply the numbers outside the radical together.

$$=8\cdot\sqrt2 \\~\\ =8\sqrt2$$

hectictar May 4, 2017
#3
+2

are you a math major or something you explain it so well

#4
+5

Lol! I am still in high school....though just barely!! But I really appreciate it!   hectictar  May 4, 2017
edited by hectictar  May 4, 2017
#5
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im a sophmore and im curently failing algebra so yea imma be on this sight alot

#6
+1

I ma in 3rd grade and I can do this problem it's sqrt(2)*8 because 128 is 2^8. it is 8sqrt2

Guest May 6, 2017