Unanswered question about angles...

LambLamb has given the correct answer.....note......

tan x  =  0   at

0, 180, 360, 540, 720, 900, 1080, 1260, 1440

So......dividing each angle by 4, we have

0, 45, 90, 135 , 180, 225, 270, 315 , 360

So.....the general solution is    0 + n45°   or   0 + n(pi/4)  in radians

I'll see what I can do.

2 tan 4x -1/2 = -1/2

(+1/2 to both sides)

2 tan 4x =0

(both sides divided by 2)

tan4x = 0/2 = 0

(inverse tan of both sides)

4x = 0

(divide both sides by 4)

x = 0/4 = 0

0 is your answer.

A general answer would be \(0+\frac{nπ}{2}\)

Shades, I really, truly, hope you found this helpful. I'm sorry it took 2+ hours to get to this question, and I hope you haven't given up.

Here's one instance of an angle sequence:

-2π, -3π/2, -π, -π/2, 0, π/2, π, 3π/2, 2π

Alright, the only thing is, I am generally supposed to have an angle for an answer, such as 15^o, 10^o, etc. Usually there is a sequence of angles that will work for the equation as well.

Here is an example of what I usually deal with:

sin 3x = 1/2

The answer to this being 10⁰, 130⁰, 250⁰, 150⁰, 170⁰, 290⁰ All of the angles that can be multiplied by 3 and then the sin will equal 1/2, or .5.

0° and multiples of 180°

Like this: 0°, 180°, 360°, 540°, 720°, etc.

edit: multiples of 45° also work.

Talk about the blind leading the blind !

Melody or some other moderator, please intervene.

Thank you everyone very much, this has helped me very much!

Uh.....Guest.....I might be blind, but  I'm not stupid........here's a graph of the solutions.....I think you will find that it matches  my answer........

https://www.desmos.com/calculator/idt39vmsqs

The comment referred to responses #1 to #5.

#6 was posted just seconds before #7.