A large lot of items includes 10% defectives. Thus the chance of selecting a defective item is 0.1 and conversely, the chance of selecting a good item is 0.9. Compute to 4 decimal places, the chance of getting 1 or 2 defectives. Consider n=10.
I assume n=10 to mean "10 consecutive draws", then:
.9^10=0.3486784401 probsbility of NOT selecting a defective item. Therefore,
1 - 0.3486784401=0.6513215599 probability of selecting1 defective item.
0.6513215599^2=0.424219......... probability of selecting 2 defective items.
CPhill: Please verify these figures. Thanks.
