Find the units digit of 13^19 *19 ^13
I already tried an answer but got it wrong. Can someone please explain how to do this problem?
The units digit for powers of three is: 3,9,7,1,3... The 19th number will be 7.
The pattern for 9 is: 9,1,9... and the thirteenth number will be 9
Then we have 7*9, which has a units digit of 3
The units digit for powers of three is: 3,9,7,1,3... The 19th number will be 7.
The pattern for 9 is: 9,1,9... and the thirteenth number will be 9
Then we have 7*9, which has a units digit of 3