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hi i want tell me what to do to prove the following it is up blocked 

 

αν=ν!/ν^ν i think with berrnulli,(general say:(1+x)^ν ≥ 1+χν 

 

so in this case :       

 

v!=1 x 2 x...x (v-1) x v  and v^v with bernulli : v^v=(1+(v-1))^v ≥ 1+(v-1)v   (x is the symbol of multiplication) 

 

                        1 x 2 x...x (v-1) x v        1 x 2 x...x (v-1) x v 

so :       αν ≤     -------------------------  ≤  --------------------------- =   1 x 2 x...       but i want it be = 1 

                               1+(v-1)v                        (ν-1)ν                     

 

 

 

 

Please i want your help.Sry for my bad english

DimitrisThymaras  Oct 22, 2017
edited by DimitrisThymaras  Oct 22, 2017
edited by DimitrisThymaras  Oct 22, 2017
edited by DimitrisThymaras  Oct 22, 2017
 #1
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You mean \(av \le \frac{v!}{v^{2}-v+1} \le \frac{v!}{v^{2}-v} = 1 \times 2 \times \dots\) right?

helperid1839321  Oct 25, 2017

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