Suppose that x,y,z are positive integers satisfying x ≤ y ≤ z, and such that the product of all three numbers is twice their sum. What is the sum of all possible values of z?
318 , 415 , 514 , 813>> Total = 4
The answer is 22.
22 is incorrect guest, but thanks for trying!
4 is also incorrect, guest. Thanks for your effort!
1 = (2, 2, 4) 2 = (1, 4, 5) 3 = (1, 3, 8)
So would the answer be
(2+2+4)+(1+4+5)+(1+3+8)?
Thank you, but it says that is incorrect.
1 - (2 * 2 * 4) ==2 * (2 + 2 + 4) ==16 = 16
2 - (1 * 4 * 5) ==2 * (1 + 4 + 5) ==20 = 20
3 - (1 * 3 * 8) ==2 * ( 1+ 3 + 8) ==24 = 24
Sum of all possible value of z ==4 + 5 + 8 ==17
Both of those are also incorrect, I'm so sorry. I appreciate your help though!
159 167 235 333 Total = 4
Then the sum of all possible values of z is 9 + 7 + 5 + 3 = 24.
That was wrong, sorry.
+660 
