In the figure below, D is a point on segment CE such that AD || BE and A is not on BC. Line segments AD and BC intersect at P.
And... what's the question?¿?
Angles CAD and CBE can be equal! We can't let A be on BC, but we can adjust the position of B so that AC and BC are very close to each other. Then if they are close enough, since AD and BE are parallel, we can make anlges CAD and CBE equal.