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The value of y varies inversely as x and when x=2, y=4. What is x when y=1?

 Apr 5, 2022
 #1
avatar+37165 
+1

y = k / (sqrtx)

y sqrt x = k

4 (sqrt2) = k

 

1 = 4 sqrt 2  / x

x = 4 sqrt 2

 Apr 6, 2022
 #2
avatar+46 
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Unfortunately, that answer is wrong. The correct answer is 32.

SpaceXGeek  Apr 6, 2022
 #4
avatar+37165 
+1

Yeppers.....As Melody stated.....I left out the sqrt on the denominator

 

1 = 4 sqrt 2  / sqrt x

sqrt x = 4 sqrt 2            now, square both sides

x = 32

 

surprise

ElectricPavlov  Apr 6, 2022
 #3
avatar+118696 
+1

You forgot the sqrt on the bottom EP, just a trivial mistake that SpaceX should have picke  up for himeself.

 

y=kx(2,4)4=k2k=42y=42xwheny=11=42x1=32xx=32

 Apr 6, 2022

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