The value of y varies inversely as \(\sqrt{x}\) and when \(x =2\), \(y=4\). What is x when y=1?
y = k / (sqrtx)
y sqrt x = k
4 (sqrt2) = k
1 = 4 sqrt 2 / x
x = 4 sqrt 2
Yeppers.....As Melody stated.....I left out the sqrt on the denominator
1 = 4 sqrt 2 / sqrt x
sqrt x = 4 sqrt 2 now, square both sides
x = 32