+0  
 
0
160
4
avatar+46 

The graphs of $2y + x + 3 = 0$ and $3y + ax + 2 = 0$ are perpendicular. Solve for $a.$

 Apr 17, 2021

Best Answer 

 #2
avatar+35059 
+3

If they are perpindicular , then the slope, m of line 1   will be   - 1/m of the second line...

   re-arrange the equations into   y = mx + b form to easily see the slopes

 

2y + x + 3 = 0   becomes

y = - 1/2 x - 3/2      slope , m = - 1/2     does the slope of the other line = - 1/ (-1/2) = 2 ???

 

second line

3y + ax + 2 = 0

3y= - ax - 2

y = - a/3 x - 2/3       to be perpindicular    - a/3 must equal 2

                                        - a/3 = 2

                                            a = -6

 Apr 17, 2021
 #1
avatar
0

A is... Never mind you got someone else that is about to answer :/

 

Bye~Hannah

 Apr 17, 2021
 #3
avatar+309 
+1

Sign up guasts! 

WillBillDillPickle  Apr 17, 2021
 #4
avatar
0

Cant I've tried it wont send me an email

Guest Apr 17, 2021
 #2
avatar+35059 
+3
Best Answer

If they are perpindicular , then the slope, m of line 1   will be   - 1/m of the second line...

   re-arrange the equations into   y = mx + b form to easily see the slopes

 

2y + x + 3 = 0   becomes

y = - 1/2 x - 3/2      slope , m = - 1/2     does the slope of the other line = - 1/ (-1/2) = 2 ???

 

second line

3y + ax + 2 = 0

3y= - ax - 2

y = - a/3 x - 2/3       to be perpindicular    - a/3 must equal 2

                                        - a/3 = 2

                                            a = -6

ElectricPavlov Apr 17, 2021

21 Online Users