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pleae help the following:

 Feb 1, 2016
 #1
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(a) 4 sinx +  3cos(x + pi/3)  = 2

 

4sinx + 3 [ cosxcos(pi/3) - sinxsin(pi/3)]  = 2

 

4sinx + [3/2]cosx - (3*sqrt(3)/2)sinx  = 2

 

8sinx + 3cosx - 3sqrt(3) sinx  = 4

 

[8 - 3sqrt(3)]sinx - 4  =   3cosx        square both sides

 

[91 - 48*sqrt(3)]sin^2x - [64 - 24*sqrt(3)] sinx + 16 = 9[cos^2x]

 

[91 - 48*sqrt(3)]sin^2x - [64 - 24*sqrt(3)] sinx + 16 = 9 - 9sin^2x

 

[100 - 48*sqrt(3)]sin^2x - [64 - 24*sqrt(3)] sinx + 7  = 0

 

Let a  =  sinx    and we have

 

[100 - 48*sqrt(3)]a^2  - [64 - 24*sqrt(3)] a  + 7  =  0

 

And using the quadratic formula, we have

 

a = 1/2   so    sinx = 1/2    and this happens at  pi/6  rads

 

or

 

a ≈ .83029    so  sinx ≈ .83029   and, taking the sine inverse of .83029,  this occurs at about .9796 rads

 

Here's a graph that confirms both results  : https://www.desmos.com/calculator/dl9hzyg9b0

 

 

cool cool cool

 Feb 2, 2016

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