Urgent

For this problem, we have to divide 1000 km by the product of hours per day and average speed:

$days=\frac{1000}{10*8=80}$

$days=\frac{960+40}{80}$

$days=\frac{960}{80}+\frac{40}{80}$

$days=12+\frac{1}{2}$

$days = 12.5$

Stewart will take 12.5 days to travel 1000km.

Stewart cycles at an average speed of 10 kilometres per hour.

How many days will it take him to travel 1000 kilometres,

if he cannot cycle more than 8 hours per day?

$\begin{array}{|rcll|} \hline && 1000\ km \cdot \frac{1\ \text{hour}}{10\ km}\cdot \frac{1\ \text{day}}{8\ \text{hour}} \\ &=& \frac{1000}{10\cdot8} \ \text{days} \\ &=& \frac{100}{8} \ \text{days} \\ &=& \frac{25}{2} \ \text{days} \\ &=& 12.5 \ \text{days} \\ \hline \end{array}$

It will take him to travel 1000 kilometers about 12.5 days