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How many different three-letter sets of initials are possible using the letters A through G

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 Jan 26, 2019
edited by Guest  Jan 26, 2019
 #1
avatar+3976 
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\(\text{The letters A through G can be coded as 0 through 6}\\ \text{and thus a 3 letter set is equivalent to a 3 digit base 7 number}\\ \text{There are }7^3=343 \text{ such numbers and thus 343 sets of initials}\)

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 Jan 26, 2019
edited by Rom  Jan 26, 2019
 #2
avatar+255 
+1

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There are 7 possibilities (A~G) for the first letter, 7 for the second, and 7 for the third. Multiplying this together, we get 7^3=343 total ways to make a set of 3-letter initials. 

 Jan 26, 2019

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