+0  
 
0
1636
1
avatar

(Use c=f*lamda) calculate the frequency of green light with 545 nm (1nm = 10 to the -9th power)

physics
Guest Apr 28, 2015

Best Answer 

 #1
avatar+20549 
+10

(Use c=f*lamda) calculate the frequency of green light with 545 nm (1nm = 10 to the -9th power)

$$\boxed{\; c = f\cdot \lambda \qquad \text{ or }\qquad \lambda=\dfrac{c}{f} \qquad \text{ or }\qquad f=\dfrac{c}{\lambda}
\qquad
\begin{array}{rcl}
c &=& \small{\text{ speed of light in vacuum }} \\
\lambda &=& \small{\text{ wavelength }} \\
f &=& \small{\text{ wave's frequency }}
\end{Array}
\; }$$

 

$$\small{\text{
$
\begin{array}{rclcc}
f &=& \dfrac{c}{\lambda} \quad & \quad c = 299\,792\,458 ~ \mathrm{\dfrac{m}{s}} \quad & \quad \lambda = 545 ~ \mathrm{nm} = 545\cdot 10^{-9} ~ \mathrm{m} \\\\
f&=& \dfrac{ 299\,792\,458 ~ \mathrm{\dfrac{m}{s}} }{545\cdot 10^{-9} ~ \mathrm{m} } \\\\
f&=& \dfrac{ 2.99\,792\,458\cdot 10^{8} ~ \mathrm{\dfrac{m}{s}} }{545\cdot 10^{-9} ~ \mathrm{m} } \\\\
f&=& \dfrac{ 2.99\,792\,458 }{545}\cdot 10^{8}\cdot 10^{9} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.00550077905\cdot 10^{17} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.550077905\cdot 10^{-2}\cdot 10^{17} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.550077905\cdot 10^{15} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.550077905\cdot 10^{15} ~ \mathrm{ Hz } \\\\
f &=& 0.550077905 ~ \mathrm{ PHz } \quad & \quad \mathrm{ PHz } = \mathrm{ Petahertz }\\\\
f &=& 550.077905 ~ \mathrm{ THz } \quad & \quad \mathrm{ THz } = \mathrm{ Terahertz }
\end{array}
$}}$$

 

 

heureka  Apr 28, 2015
 #1
avatar+20549 
+10
Best Answer

(Use c=f*lamda) calculate the frequency of green light with 545 nm (1nm = 10 to the -9th power)

$$\boxed{\; c = f\cdot \lambda \qquad \text{ or }\qquad \lambda=\dfrac{c}{f} \qquad \text{ or }\qquad f=\dfrac{c}{\lambda}
\qquad
\begin{array}{rcl}
c &=& \small{\text{ speed of light in vacuum }} \\
\lambda &=& \small{\text{ wavelength }} \\
f &=& \small{\text{ wave's frequency }}
\end{Array}
\; }$$

 

$$\small{\text{
$
\begin{array}{rclcc}
f &=& \dfrac{c}{\lambda} \quad & \quad c = 299\,792\,458 ~ \mathrm{\dfrac{m}{s}} \quad & \quad \lambda = 545 ~ \mathrm{nm} = 545\cdot 10^{-9} ~ \mathrm{m} \\\\
f&=& \dfrac{ 299\,792\,458 ~ \mathrm{\dfrac{m}{s}} }{545\cdot 10^{-9} ~ \mathrm{m} } \\\\
f&=& \dfrac{ 2.99\,792\,458\cdot 10^{8} ~ \mathrm{\dfrac{m}{s}} }{545\cdot 10^{-9} ~ \mathrm{m} } \\\\
f&=& \dfrac{ 2.99\,792\,458 }{545}\cdot 10^{8}\cdot 10^{9} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.00550077905\cdot 10^{17} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.550077905\cdot 10^{-2}\cdot 10^{17} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.550077905\cdot 10^{15} ~ \mathrm{\dfrac{1}{s}} \\\\
f &=& 0.550077905\cdot 10^{15} ~ \mathrm{ Hz } \\\\
f &=& 0.550077905 ~ \mathrm{ PHz } \quad & \quad \mathrm{ PHz } = \mathrm{ Petahertz }\\\\
f &=& 550.077905 ~ \mathrm{ THz } \quad & \quad \mathrm{ THz } = \mathrm{ Terahertz }
\end{array}
$}}$$

 

 

heureka  Apr 28, 2015

20 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.