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Use the change of base formula to approximate the solution to log0.515 = 1 – 2x. Round to the nearest hundredth.

Guest Jun 9, 2015

Best Answer 

 #1
avatar+87301 
+10

I'm not sure that the change of base formula would do much good here, since we're already using base 10....here's my approach...

 

log0.515 = 1 – 2x     and we can write

 

log0.515  = log 10 - 2x    rearrange

 

2x = log 10  - log0.515

 

2x = log (10/0.515)    divide both sides by 2

 

x = log(10/0.515)/ 2   ≈ 1.288  ≈  1.29 to the nearest hundredth

 

 

CPhill  Jun 10, 2015
 #1
avatar+87301 
+10
Best Answer

I'm not sure that the change of base formula would do much good here, since we're already using base 10....here's my approach...

 

log0.515 = 1 – 2x     and we can write

 

log0.515  = log 10 - 2x    rearrange

 

2x = log 10  - log0.515

 

2x = log (10/0.515)    divide both sides by 2

 

x = log(10/0.515)/ 2   ≈ 1.288  ≈  1.29 to the nearest hundredth

 

 

CPhill  Jun 10, 2015
 #2
avatar+92781 
0

Hi Chris

I couldn't work out what was wanted either  

Your answer is a good one though. 

Melody  Jun 10, 2015

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