Use the diagram to find the measure of exterior angle BCD.
Triangle A B C has angles labeled as follows: A, (101x + 2) degrees; B, 34x degrees; C, unlabeled. Point C lies on Ray A D. The outside angle B C D is labeled (138x - 1) degrees. left parenthesis 138 x minus 1 right parenthesis degrees(138x − 1)°
34 x degrees34x° left parenthesis 101 x plus 2 right parenthesis degrees(101x + 2)° DCAB
The measure of exterior angle BCD is
(101x + 2) + 34x + C = 180, solve for C
C =178 - 135x
(178-135x) + (138x - 1) = 180, solve for x
x = 1, so:
Angle BCD =(138x1 -1) =137 Degrees.