+59 Use the quadratic formula to solve these equations, showing work. Of course, every equation's value of x is independent from the rest.
(x^2) + 4x - 2 = 0
-6(x^2) + 3x + 2 = 3
-(x^2) +1 = -5(x^2) + 4x
2(x - 3)^2 = -2x + 9
+118678 Come on Shadew, we are not here to do all your homework for you.
The first one can just get plugged straight into the quadratic formula a=1, b=4 and c=-2
The others you need to simplify so that they are in the form $$ax^2+bx+c=0$$ first.
this might help
+59 Well, to be fair, that isn't all of it.
But I seriously thought the point of this site was to get help with math homework. Granted, I could (and should) have just asked for you guys to answer one and then applied the steps to the rest.
+129852 Shadew.....let us know if you have trouble putting any of them in S.F.......once you do that....it's just "plug and play," basically.......
+59 Well, if you wouldn't mind helping w/ one of those two-sided ones, that'd be great. Is it done the same way, just using the formula on both sides?
+129852 No....we want everything on the same side - I prefer the left side, myself
For instance....this one...
-(x^2) +1 = -5(x^2) + 4x add 5x^2 to both sides and subtract 4x from both sides
4x^2 - 4x + 1 = 0 so...a = 4 b = -4 and c = 1 (got it ???)
(Actually....I wouldn"t even use the Q formula on this one....it can be factored and solved directly.....!!!.......but if that's what they're asking you to do.....)
+118678 You have to get them all to one side an = 0 first.
eg
$$\\2(x - 3)^2 = -2x + 9\\
2(x - 3)(x-3) = -2x + 9\\
2(x^2-6x+9) = -2x + 9\\
2x^2-12x+18 = -2x + 9\\
2x^2-12x+2x+18-9 = -2x+2x + 9-9\\
2x^2-10x+9 = 0\\\\
a=2,\;\; b=-10,\;\; c=9$$
+26393 Use the quadratic formula to solve these equations
https://www.youtube.com/watch?v=ZywdPuXR0S0
nice song about quadratic formula
