Use the Squeeze Theorem to evaluate the limit \( \displaystyle \lim_{x\to 6} f(x)\), if
\(12 x - 36 \leq f(x) \leq x^2 \qquad \textrm{on} \; [4, 8].\)
Can someone help to explain this problem and show me how to get the answer?
I barely remember this but I'll take my best shot
Note that as x approaches 6, the function 12x - 36 = 12 (6) - 36 = 72 -36 = approaches 36
And as x approaches 6, the function x^2 = 6^2 = approaches 36
So.....by the Squeeze Theorem......f(x) also approaches 36 as x approaches 6 [ i.e., the limit =36 ]