#1**+2 **

First find the vertex.....can you tell me what that is?

From the graph the vertex is h,k (or the x,y point) = -3,4

Vertex form of parabola......we answered that in your las question....remember it?

y = a(x-h)^2 +k is vertex form Now let's put -3 , 4 in there

y= a (x-(-3))^2 + 4 Now how can we find the value of 'a' ? find a convenient point on the graph (not the vertex) ....look at x = -5 at that point y = -4 Sub this in to the working equation then solve for 'a'

-4 = a (-5 +3)^2 +4 means 'a' = -2 soooooo the equation becomes

y = -2(x+3)^2 +4

ElectricPavlov Feb 20, 2018

#1**+2 **

Best Answer

First find the vertex.....can you tell me what that is?

From the graph the vertex is h,k (or the x,y point) = -3,4

Vertex form of parabola......we answered that in your las question....remember it?

y = a(x-h)^2 +k is vertex form Now let's put -3 , 4 in there

y= a (x-(-3))^2 + 4 Now how can we find the value of 'a' ? find a convenient point on the graph (not the vertex) ....look at x = -5 at that point y = -4 Sub this in to the working equation then solve for 'a'

-4 = a (-5 +3)^2 +4 means 'a' = -2 soooooo the equation becomes

y = -2(x+3)^2 +4

ElectricPavlov Feb 20, 2018