+0  
 
-4
760
6
avatar+73 

Use three different ways (graph, table, algebraically) to convince someone that

 Mar 6, 2019
edited by GAMEMASTERX40  Mar 6, 2019
 #1
avatar+129847 
+2

Graph : This is symmetric with the y axis....this is characteristic of an even function

Graph here : https://www.desmos.com/calculator/w76y3q8fup

 

Table

x  y

1  4

-1 4         this is also characteristic of an even function...  if (-x, y) is on the graph....then so is (x , y)

 

Algebraically

 

If f(x) = f(-x)....then even

f(x) = x^2 + 3

f(-x) = (-x)^2 + 3  =  x^2 + 3   =  f(x)...so.....even

 

 

cool cool cool

 Mar 6, 2019
 #2
avatar+73 
-6

Thanks, CPhill! Also, can you check my work if it is correct? It was a post from a few days before but I just forgot to respond back. There is also have been some guests insulting me for no reason what so ever. Maybe you should check on it.

 

https://web2.0calc.com/questions/for-each-of-the-following-determine-the-integer-value

GAMEMASTERX40  Mar 6, 2019
 #3
avatar+129847 
+1

Just ignore these people....remember....their words can't hurt you on here !!!

 

 

And..I'll check...

 

 

cool cool cool

CPhill  Mar 6, 2019
 #4
avatar+129847 
+1

Your solutions are correct....!!!!

 

 

cool cool cool

CPhill  Mar 6, 2019
 #5
avatar+73 
-6

Thanks, I understand it now. I have been struggling with these kinds of problems for a certain reason which is stressing me. I don't know why people on this forum are attacking me just for posting math here when I didn't do anything to others. Can you like delete those messages knowing that you're a moderator?

GAMEMASTERX40  Mar 6, 2019
edited by GAMEMASTERX40  Mar 6, 2019
edited by GAMEMASTERX40  Mar 6, 2019
 #6
avatar+129847 
+1

I'll make those posts invisible...and I agree....you shouldn't be attacked...just because it might be easy for others doesn't mean that it's easy for everyone....

 

cool coolcool

CPhill  Mar 6, 2019

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