What is the hypotenuse of a right triangle with the two leg lengths at 4 times the square root of 2 and 7?
Hypotenuse =
sqrt ( (4√2)^2 + 7^2 ) = [ note 4√2 = √(16 *2) = √32 ]
sqrt ( √32)^2 + 49) =
sqrt ( 32 + 49) =
sqrt (81) =
9 units
Here's another one,
Hypotenuse is 13, one leg is 12, what is the other leg?
(13^2)-(12^2)=25
sqrt(25)=5
