+0  
 
0
118
3
avatar+597 

Hi friends,

 

I may have been explained this before, but I just cannot get my head around this, no matter how I try, I just do not grasp this...may I ask just 10 min of your time to just explain this to me again, please..

 

The sum is: \(M= {{\sqrt{25-2x}} \over x}\)

 

Determine the value(s) of x for which M will be:

 

1.1) Real

1.2) Rasional

 

what confuses me is the WHY

 

WHY do they equate 25-2x greater and equal to zero for number 1?

 

for number 2, they find values for x, in this case 8 and 12. They plug them in and get answers...WHY 8 and 12?

ALSO, why not equate 25-2x = 0, or to anything else for number 2?

 

Rasional numbers are a part of REAL numbers, ....so why not treat them the same?

 

guys, I really would appreciate your assistance. Thank you all very much..

 Oct 11, 2019
 #1
avatar+106539 
+1

1)    We cannot take the square root of a negative number and get a real number returned

 

Therfore.....the quantity under the radical MUST BE ≥ 0

 

So....

 

25  - 2x ≥  0        add 2x to both sides

 

25 ≥ 2x              divide both sides by 2

 

25/2 ≥  x       which is the same as   x ≤ 25/2

 

 

cool cool cool

 Oct 11, 2019
 #2
avatar+106539 
+1

2)   Any value of x  that makes  25 - 2x  ≥ 0   but  NOT a perfect square  will mean that  a radical will still remain in the expression......and  the remaining radical WILL NOT be a rational number....to see this

 

Let x  =  2     and we have that

 

√[25 - (2)(2) ]  / 2  =  √21 / 2       and  √21/2  is NOT RATIONAL

 

So......we only get a rational  whenever x  = 8   or  x  = 12   thusly

 

√[25 - 2(8) ] / 2  =  √9 / 2  =   3/2    which  IS rational

 

And

 

√ [25 - 2(12) ] / 2  =  √1 /2  =    1/2  which is also rational

 

So...remember.....any positive integer  under the radical that is not a perfect square will produce an irrational

 

Hope that helps  !!!

 

cool cool cool

 Oct 11, 2019
edited by CPhill  Oct 11, 2019
 #3
avatar+597 
+1

CPill,

 

Thank you for your time, I am going to spend some time with examples of these types of questions, however I am sure the light will go on...smiley..I honestly do appreciate!!..have a blessed day...

juriemagic  Oct 11, 2019

15 Online Users

avatar
avatar
avatar