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The number of greens varied directly as the square root of the number of reds and inversely as the number of whites squared. What happens to the number of greens if the number of reds is multiplied by 16 and the number of whites is doubled?

Let G = greens R = reds W = whites..................halp

 Feb 25, 2016

Best Answer 

 #1
avatar+23252 
+15

Let k = proportionality factor.

G = k·sqrt(R) / W2

When the reds are multiplied by 16 and the number of whites is doubled:

G = k·sqrt(16·R) / (2·W)2

Simplifying:

G = k·4·sqrt(R) / (4·W2)

So:  G = k·sqrt(R) / W2

The equation remains unchanged, since sqrt(16) = 4 and 2 squared = 4, and these 4s cancel.

 Feb 25, 2016
 #1
avatar+23252 
+15
Best Answer

Let k = proportionality factor.

G = k·sqrt(R) / W2

When the reds are multiplied by 16 and the number of whites is doubled:

G = k·sqrt(16·R) / (2·W)2

Simplifying:

G = k·4·sqrt(R) / (4·W2)

So:  G = k·sqrt(R) / W2

The equation remains unchanged, since sqrt(16) = 4 and 2 squared = 4, and these 4s cancel.

geno3141 Feb 25, 2016

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