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Pre-calculus/trig

 Apr 8, 2019
 #1
avatar+106519 
+2

We have orthogonal vectors when their dot products  = 0

 

So

(2, 1) dot (-3, 6)  =  -6 +6  =  0    orthogonal

 

(2, 1) dot (  1, 2 )  = 2 + 2   = 4    not  orthogonal

 

(2, 1) dot ( -2, - 3)  = -4 + -3  =  -7     not orthogonal

 

(2, 1) dot ( 1, - 2)  = 2 + -2  =  0       orthogonal

 

[ I'm assuming that your are familiar with dot products ....]

 

 

cool cool cool

 Apr 9, 2019
 #2
avatar+315 
+1

Yes, I am familiar with dot products... thank you! smiley

Cupcake  Apr 9, 2019
 #3
avatar+19789 
0

Similarly.....treat   2,1 as a vector    slope = rise/run =   1/2       orthoganal slope is -2

 

-3,6     rise / run =   6/-3 = -2    orthogonal

 

1,2     2/1 = 2    nope

-2,-3     -3/-2     nope

1, -2     -2/1     orthogonal

 Apr 9, 2019
 #4
avatar+106519 
0

Thanks, EP.....I hadn't thought about that method   !!!!

 

 

cool coolcool

CPhill  Apr 9, 2019

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