+0  
 
0
589
3
avatar+279 

Could someone please help me with this problem? I'm very confused and I don't even know where to start. I tried to do it on my own, but I think I'm missing something:(

https://web2.0calc.com/questions/vectors_25

 May 24, 2020
 #1
avatar+36916 
+2

A ship leaves port at noon and travels at a bearing of 214°. The ship’s average rate of speed is 15 miles per hour.

Describe the location of the ship at 2:30 p.m. by writing a vector in component form.

 

 

The component form of the vector representing the ship at 2:30 p.m. is approximately ⟨    ,    ⟩.

 

From noon to 2:30   is 2 1/2 hrs      2 1/2 hr x `15 = 37.5 miles at bearing 214o

 

the 'x' component will be    37.5 m cos 214 =  ~  -31 miles

the 'y' component will be    37.5 m sin 214 =  ~   -21 miles

 May 24, 2020
 #2
avatar+279 
0

Thank you so much! I see what I did wrong. I got the 37.5 part, but after that, I was beyond confused! I understand a lot better:)

So, would that mean the ship was 31 miles to the south and 21 miles to the west of where the ship left port? 
I graphed the point, and that's what my conclusion was, I just want to be sure! 
Thank you again xx 

auxiarc  May 24, 2020
 #3
avatar+36916 
+1

If 0 0   is considered North then yes   214 0    is south and west

ElectricPavlov  May 24, 2020

3 Online Users

avatar